Thread: Loose bearings
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Old 01-24-2006, 11:31 AM
Brian Carlton Brian Carlton is offline
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Join Date: May 2002
Location: Blue Point, NY
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Quote:
Originally Posted by sbourg
Oops, problems with posting too close to sleepitime - forgot torque-to-force conversion, among others. Tangential force at 1/2" radius from 45 ft-lbs is 1080 lbs, then tangential-to-axial conversion factor of 62.8, and we actually have 34 tons of pressure. That will seat about anything.

Steve
You're missing the point. You can't "seat" the outer race because it's already squeezed into the hub and stopped against the hub face. You could use 1000 tons and it's still going nowhere.

As far as seating the inner race, it lives on the spindle with a very slight clearance in most cases. So, seating it, axially, requires very little force. So, your desire is to simply take up the clearance between the rollers and the outer race and ensure that the bearing, with the inner race, is sitting on the axial stop within the hub. Adding more force, once the clearance is zero, won't accomplish anything. As your calculations show, you don't need much torque (5 ft.-lb. would be more than sufficient) to remove the clearance in the bearing.

Last edited by Brian Carlton; 01-24-2006 at 11:38 AM.
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